This is the transformation which is needed to convert a reading x'
in the K' system of coordinates to an x value in the K system, if K' moves
with a speed of v relative to the K system. According to classical Galileian / Newtonian
mechanics: x' = x - vt.
We are considering motion only along the x axis. y' and z'
remain the same as y and z, respectively.
A light signal along the positive x axis ( to the right )
of frame K is transformed according to the
equation x = ct, or x - ct = 0
(1)
Relative to K' the transformation is x' - ct' = 0 (2)
Space-time points ( called events ) which satisfy (1) must also satisfy (2).
i.e. where l is a constant (3)
In the negative direction where m is a constant (4)
Add (4) to (3)
i.e. (5 i)
where and .
Equation (3)
Equation (4)
Subtract (4) from (3)
So that
i.e.
..So that (5 ii)
The problem now is to find the values of a and b.
For the origin of K', x' = 0
x' = ax - bct. ( Equation (5 i) ),
becomes ax - bct = 0.
(6)
and or , and .
v is the relative velocity of the two systems of co-ordinates.
The Principle of Relativity states: Relative to K the length of a unit measuring rod at rest to K', must be exactly the same as the length of the rod relative to K' of a unit measuring rod at rest to K.
Insert a particular value of t ( time of K ), e.g. t = 0,
Then (5 i) becomes x' = ax - bc(0),
So that x' = ax
If x' increases by 1 unit ( infinitesimally small ) ax = 1 so that (7)
Relative to K' where t' = 0 , eliminating t from equations (5 i) and (5 ii)
we get: bct = ax - x' and act = ct' + bx .
Thus and so that .
so that .. .
But and from (6)
ie
so that .
Thus points on the x-axis separated by distance 1 relative to K will be represented by the distance
x' = a ( 1 - v2 / c2 )1 and this must be equal to ( from (7) )
. Therefore (8)
Equations (6) and (8)
determine the values of a and b . Insert these values of
a and b in equation (5 i) :
The
Lorentz transformation for events on the x-axis.
The time t' can be derived from:
It equals the classical transformation divided by